Given the equation:
210+210=2x
We start by recognizing the left-hand side:
210+210
We can factor out 210 from both terms:
210+210=210(1+1)
Since 1+1=2, we have:
210(1+1)=210⋅2
We can rewrite 2 as 21:
210⋅2=210⋅21
Using the property of exponents that am⋅an=am+n, we get:
210⋅21=210+1
So,
211=2x
By comparing the exponents, we find:
x=11
Thus, the value of x is 11.